Get the the difference between two dates in MS SQL

The DATEDIFF() function returns the difference between two dates
Syntax: DATEDIFF ( datepart , startdate , enddate )

Following is an example for the DateDiff()
DECLARE @startdate datetime ='2011-11-14 02:00:06.957';
DECLARE @enddate datetime = '2011-11-16 05:00:15.490';
SELECT DATEDIFF(day, @startdate, @enddate) as dayDifference,DATEDIFF(HOUR, @startdate, @enddate)as hourDifference
Output

dayDifference	hourDifference
2	51

Similarly the following are the available datepart Options on the DateDiff() Function.

year(or yy or yyyy)
quarter(or qq or q)
month (or mm or m )
dayofyear(or dy or y )
day (or dd, d )
week(or wk or ww)

hour(or hh)
minute(or mi or n)
second(or ss or s )
millisecond(or ms)
microsecond(or mcs)
nanosecond(or ns)
TZoffset(or tz)
ISO_WEEK(or isowk or isoww)

Get the Row Numbers as a separate column on MS SQL Query

I was trying to execute a new query where I need the Row number as a new column on the result itself. I used the SQL Function ROW_NUMBER() to get the row number.
Following query gives the Report Path with the HitCount along with the added Row Number.

select ROW_NUMBER() OVER(ORDER BY count(ReportPath) DESC) AS 'Row Number', ReportPath,count(ReportPath) as HitCount
FROM [ReportServer].[dbo].[ExecutionLog2]
Group by ReportPath
Order by HitCount desc


Cheers !